-3d^2-5d+5=0

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Solution for -3d^2-5d+5=0 equation: 



-3d^2-5d+5=0

a = -3; b = -5; c = +5;
Δ = b2-4ac
Δ = -52-4·(-3)·5
Δ = 85
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$d_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$d_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$d_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-5)-\sqrt{85}}{2*-3}=\frac{5-\sqrt{85}}{-6}
$


$d_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-5)+\sqrt{85}}{2*-3}=\frac{5+\sqrt{85}}{-6}
$

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